0=4x^2-6x-4

Solution for 0=4x^2-6x-4 equation:

0=4x^2-6x-4

We move all terms to the left:

0-(4x^2-6x-4)=0

We add all the numbers together, and all the variables

-(4x^2-6x-4)=0

We get rid of parentheses

-4x^2+6x+4=0

a = -4; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·(-4)·4
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-10}{2*-4}=\frac{-16}{-8}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+10}{2*-4}=\frac{4}{-8}
=-1/2
$